Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Basics Getting Started with Java IO

Tiffany Der
Tiffany Der
556 Points
Posted by Tiffany Der
Tiffany Der
556 Points

"Ensure you put the string formatter `%s` in your format string" quiz question #3. how do I put this into syntax?

I'm little confused with question#3

IO.java 
// I have imported java.io.Console for you.  It is a variable called console.
String firstName = "Tiffany";
console.readLine(firstName);
String lastName = "Der";
console.readLine(lastName);
console.printf("First name:", firstName);
console.printf(firstName);
benoit koch
benoit koch
3,875 Points
benoit koch
benoit koch
3,875 Points

String firstName=("Tiffany"); String lastName=("Der"); firstName = console.readLine("%s", firstName); lastName = console.readLine("%s", lastName); console.printf("First name:%s", firstName);

1 Answer

Steven Parker
Steven Parker
231,236 Points
Steven Parker
Steven Parker
231,236 Points

The token "%s" goes where you want the name to appear in the output string:

console.printf("First name: %s", firstName);

Also, for tasks 1 and 2, you don't need the literal strings. You can just assign the "readLine" result directly:

String firstName = console.readLine();
String lastName = console.readLine();