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JavaScript JavaScript Basics (Retired) Storing and Tracking Information with Variables Review JavaScript Variables

about the sorting in JavaScript

Hello, I saw how is the syntaxis of an object and the array. But I found in other place this kind of syntaxis: $startOptions: ( size: 5px, width: 70, height: 70,

loops: 10, twists: 10,

minHue: 360, maxHue: 360 );

Are this an array too? Since array syntaxis is like this var cars = ["Saab", "Volvo", "BMW"] Are this an object? I remember that the object has the syntax as follows: person={ size: '5px', width: 70, height: 70,

loops: 10, twists: 10,

minHue: 360, maxHue: 360 };

But in this example I found it uses parentesis and the 5px is not between quotations...

Thanks

2 Answers

Steven Parker
Steven Parker
231,275 Points

Your first example is not an array. But it also doesn't follow the convention for objects, for the reasons you pointed out.

My first guess would be that this exampe is not JavaScript code. Please provide a link to the place where you saw this, and I'll give you a more detailed answer.

Steven Parker
Steven Parker
231,275 Points

I don't know much about SCSS/Sass, but I'd guess that the argument passed to the parameter "$shadow" represents another function that will be dynamically invoked by the "call" method.

There are Sass courses here if you're interested in learning more.

oh well you're right. It's SCSS. Here is the link https://codepen.io/ruberoctavio/pen/RejjVw

Also, I don't understand this part: @function hueRange($shadow, $hue) { $minHue: call($shadow, minHue); $maxHue: call($shadow, maxHue); @return $hue / 360 * ($maxHue - $minHue) + $minHue; }

As you can see $minHue and $maxHue uses a call method (I couldn't find details about it). And, the function asks for 2 arguments but $shadow is not used anywhere..

I quite donΒ΄t understand the logic of it...

Steven Parker
Steven Parker
231,275 Points

I added a comment to my original answer.