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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

After your newly created returnValue function, create a new variable named echo. Set the value of echo to be the results

After your newly created returnValue function, create a new variable named echo. Set the value of echo to be the results from calling the returnValue function. When you call the returnValue function, make sure to pass in any string you'd like for the parameter.

The function will accept the string you pass to it and return it back (using the return statement). Then your echo variable will be set with what is returned, the results.

script.js
function returnValue(drink) {
return drink;
}
index.html
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

1 Answer

Christopher Collins
seal-mask
.a{fill-rule:evenodd;}techdegree
Christopher Collins
Front End Web Development Techdegree Student 6,343 Points

Hi Amrita,

This question is aimed at making sure we understand how parameters and arguments are passed in and between functions and the JS code. Below is the solution to the challenge:

function returnValue (drink) { return drink; }

var echo = returnValue('pepsi');

We can see that the function can accept one argument (drink), which it will then feed down into its internal code block for processing. As this particular function only returns the value directly, when we call the function below we can send it whatever answer we desire ('pepsi')/('orange juice')/('water')/('coffee').

Hope this helps!