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iOS Swift Collections and Control Flow Control Flow With Conditional Statements FizzBuzz Challenge

Posted by Courtney Cassar
Courtney Cassar
1,407 Points

Again, not sure what I'm doing wrong here... even after looking at the solution it's still not working.

it keeps coming up with '(Int) -> String does nor conform to protocol 'Sequence' could someone explain what this error means? I am taking an Int and it is outputting a string

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers

         for n in fizzBuzz {
        if (n % 3==0) && (n % 5)==0 {
    print("FizzBuzz")
        } else if (n % 3==0) {
            return"Fizz"
        } else if (n % 5 == 0){
            return"Buzz"
        } else {
            return(n)}
  }
    }
  // End code

1 Answer

Aniruddha Shukla
Aniruddha Shukla
2,846 Points
Aniruddha Shukla
Aniruddha Shukla
2,846 Points

Your syntax is wrong. The default case you are returning an Integer when your function is saying it returns a String. This should work

func fizzBuzz(n: Int) -> String {
    // Enter your code between the two comment markers

        if ((n % 3 == 0) && (n % 5 == 0)) {
            return "FizzBuzz"
        } else if (n % 3==0) {
            return"Fizz"
        } else if (n % 5 == 0){
            return"Buzz"
        }
    return "\(n)"
}