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Start your free trialCarlos Lantigua
5,938 PointsAJAX basics Stage 4 challenge Code not working :,,, (
When I try to run this I get the following error message in the console Failed to load resource: the server responded with a status of 404 ()
when I click on the link it says that it's a bad link. But I don't see any issues with my API link.
$(document).ready(function() {
$('form').submit(function (evt) {
evt.preventDefault();
var $searchField = $('#search');
//the AJAX part
var flickerAPI = "http://api.flickr.com/services/feeds/photo_public.gne?jsoncallback=?";
var animal = $searchField.val();
var flickrOptions = {
tags: animal,
format: "json"
};
function displayPhotos(data) {
var photoHTML = '<ul>';
$.each(data.items,function(i,photo) {
photoHTML += '<li class="grid-25 tablet-grid-50">';
photoHTML += '<a href="' + photo.link + '" class="image">';
photoHTML += '<img src="' + photo.media.m + '"></a></li>';
}); // end each
photoHTML += '</ul>';
$('#photos').html(photoHTML);
}
$.getJSON(flickerAPI, flickrOptions, displayPhotos);
}); // end click
}); // end ready
1 Answer
Steven Parker
231,172 PointsIt looks like you have a typo in your URL. You have "photo_public.gne" instead of "photos_public.gne" (with an "s").
Carlos Lantigua
5,938 PointsCarlos Lantigua
5,938 PointsThanks, I’ve come to realize one of the hardest parts of coding is type-o haha