Asynchronous Call

Question

I can't find the error in the code, please help! :)

MovieActivity.java

import android.app.Activity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import java.io.IOException;

public class MovieActivity extends Activity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_movie);

        // Get some movie information!
        String apiUrl = "http://api.rottentomatoes.com/api/public/v1.0/movies.json?apikey=xyz&q=hobbit";
        OkHttpClient client = new OkHttpClient();
        Request request = new Request.Builder()
                .url(apiUrl)
                .build();
      Call call = client.newCall(request);
      call.enqueue(new Callback()) {

                @Override
                public void onFailure(Request request, IOException e) { }                }

                @Override
                public void onResponse(Response response) throws IOException { }
    }

}

Answer 1 · 2015-11-14T02:17:58Z

November 14, 2015 2:17am

Hi,

basically what you did was close the enqueue() method after you passed in new Callback. There shouldn't be a closing parantheses there. The enqueue method should contain the entire call back like below:

      call.enqueue( //open parantheses. all the fun stuff goes in here :)
        new Callback() {
    @Override
    public void onFailure(Request request, IOException e) { }

    @Override
    public void onResponse(Response response) throws IOException { }
}
        ); //close parantheses

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Konstantinos Stoumpos

Konstantinos Stoumpos

Asynchronous Call

1 Answer

Kevin Faust

Kevin Faust