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JavaScript JavaScript Loops Working with 'for' Loops Refactor Code with a Loop

S M Tasfiqul Asif
S M Tasfiqul Asif
11,514 Points

Can someone please tell me why am I getting an error?

for (let i = 2; i <= 24; i=i+2) { console.log(i); }

script.js
console.log(2);
console.log(4);
console.log(6);
console.log(8);
console.log(10);
console.log(12);
console.log(14);
console.log(16);
console.log(18);
console.log(20);
console.log(22);
console.log(24);


for (let i = 2; i <= 24; i=i+2) {
  console.log(i);
}

2 Answers

Steven Parker
Steven Parker
231,269 Points

The instructions say to "Rewrite (or refactor) the code using a loop.", so what they want is for for you to replace the code with a loop to produce the same output after conversion. Adding a loop after the original code causes it to produce twice as much output.

Another hint is in the error message you get: "Bummer: Your code should call console.log() one time only."

Jamie Reardon
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Jamie Reardon
Treehouse Project Reviewer

Hi S M Tasfiqul Asif if this is all of your code, then this code seems valid. The only thing I can think of that you could change is the way you are updating the counter variable, you can shorten the syntax from i=i+2 to i += 2.

for (let i = 2; i <= 24; i += 2) {