Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Shopping List App Break

courtney seward
courtney seward
3,292 Points

Can someone tell me what I am doing wrong here? I would really appreciate it!

Please help me correct the answer to this question!

breaks.py
def loopy(items):
    for thing in items:
        if thing == "STOP":
        break
    else:
        print(thing)

2 Answers

Steven Parker
Steven Parker
231,269 Points

You appear to have an indentation problem.

An if and its associated else should always line up, and anything that is part of either condition should be indented one more stop.

jacksonpranica
jacksonpranica
17,610 Points

Agreeing with Steven Parker here,

Your tabbing is off, additionally you could just exclude the else statement.

def loopy(items):
    for thing in items:
        if thing == "STOP":
            break
        else:
            print(thing)

OR

def loopy(items):
    for thing in items:
        if thing == "STOP":
            break

        print(thing)