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Python Python Basics (2015) Shopping List App Break

Posted by Vu Doan
Vu Doan
2,957 Points

Can you help me with this code?

PART 1. "I need you to help me finish my loopy function. Inside of the function, I need a for loop that prints each thing in items. def loopy(items): "

my code: def loopy(items): print(items)

The code worked!

PART 2. "Oops, I forgot that I need to break out of the loop when the current item is the string "STOP". Help me add that code!"

my code: def loopy(items) if items == "STOP": break loopy("STOP")

Can you help me with the solution? Thank you!

breaks.py 
def loopy(items):
    print(items)

def loopy(items):
    of items == "STOP":
        break

loopy("STOP")

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Here's a few hints:

  • you should only have one "def" line
  • the code has "of" but I think you intended "if"
  • to end the loop without printing "STOP", the test and break must come before the "print"
  • you only need to define the function, you don't need to also call it
Vu Doan
Vu Doan
2,957 Points

Hey Steven--thank you for the hints. I still can't get it to work. Can you help me write this code?

def loopy(items): if items == "STOP": break print(items)

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

That looks like the correct order but it's hard to be sure without seeing the indentation. Use the instructions for code formatting in the Markdown Cheatsheet pop-up below the "Add an Answer" area. :arrow_heading_down:   Or watch this video on code formatting.