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Java Java Basics Perfecting the Prototype Looping until the value passes

Posted by Blessing Chiwaura
Blessing Chiwaura
18,037 Points

cant find error

whats wrong here. cant find the error

Example.java 
// I have initialized a java.io.Console for you. It is in a variable named console.
String response = console.readLine("Do you understand do while loops?");
if (response.equals("No")){
  do {
    console.printf("try again");
    System.exit(0);
      }while (response.equals("No"));
  }

2 Answers

anil rahman
anil rahman
7,786 Points
anil rahman
anil rahman
7,786 Points 
String response = "";  //make variable

    do {
      response = console.readLine("Do you understand do while loops?");  //prompt here and set the response

        }while (response.equalsIgnoreCase("no")); //ignore casing of the response

console.printf("Because you said %s, you passed the test!",response); //give the reply
Jeremy Hill
Jeremy Hill
29,567 Points
Jeremy Hill
Jeremy Hill
29,567 Points

The System.exit(0) line will cause it to exit the entire program during the first loop every time- that line isn't needed. It should look like this:

// I have initialized a java.io.Console for you. It is in a variable named console.
String response = "";

do{
  response = console.readLine("Do you understand do while loops?"); 
} while(response.equalsIgnoreCase("No"));

console.printf("Because you said %s, you passed the test!\n", response);