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Python Python Basics (2015) Letter Game App Even or Odd Loop

gokulprasath k M
gokulprasath k M
1,344 Points
Posted by gokulprasath k M
gokulprasath k M
1,344 Points

Challenge error

Need help

even.py 
import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while True:
    random_number = random.randint(1, 99)
    if random_number % 2 = 0.even_odd():
        print("{} is even".format(random_number))
    else:
        print("{} is odd".format(random_number))
start -= 1

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

You're close, but....

  • you need to check the value of start in the while loop or else it will run forever
  • when checking a number for even, just call the function: "if even_odd(random_number):"