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PHP Build a Simple PHP Application Creating the Menu and Footer Variables and Conditionals

Posted by James Hibbeard
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James Hibbeard
PHP Development Techdegree Student 13,905 Points

Confused

I am currently on the final exercise of this code challenge and its prompting me to "Change the value in the flavor variable to cookie dough. Preview the code and make sure the message appears." I tried looking over the video again to find a solution, but no luck so any idea?

3 Answers

Axel Will
Axel Will
4,022 Points
Axel Will
Axel Will
4,022 Points

The variable $flavor should go on CODELINE 2

here´s mine with "strawberry" as my favorite and the checkup if it´s also "cookie dough" after i changed my favorite to cookie dough on LINE 2 it executes the echo command.

Change the condition to == "cookie dough" before you change the variable itself to "cookie dough".

BEFORE:

$flavor = "Strawberry";

echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if ($flavor == "cookie dough"){
  echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
}
?>

AFTER:

$flavor = "cookie dough";

echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if ($flavor == "cookie dough"){
  echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
}
?>
James Hibbeard
.a{fill-rule:evenodd;}techdegree
James Hibbeard
PHP Development Techdegree Student 13,905 Points

Hey ya this is how it looks, and it is fine to section 4 but then when i change the $flavor "cookie dough" it give me an error states that I should add a condition to hide this message,

Keith Monaghan
Keith Monaghan
9,494 Points
Keith Monaghan
Keith Monaghan
9,494 Points

Which part are you stuck on? It sounds like there is a variable similar to this:

$flavor = "vanilla";

which they want changed to this:

$flavor = "cookie dough";

Does that help?

James Hibbeard
seal-mask
.a{fill-rule:evenodd;}techdegree
James Hibbeard
PHP Development Techdegree Student 13,905 Points
James Hibbeard
.a{fill-rule:evenodd;}techdegree
James Hibbeard
PHP Development Techdegree Student 13,905 Points

currently the code looks like this,

<?php

echo "<p>Your favorite flavor of ice cream is "; $flavor = "Vanilla"; echo $flavor; echo ".</p>"; if ($flavor == "Vanilla") {echo "Randy's favorite flavor is cookie dough, also!";};

?>

when i change the $flavor to cookie dough it then redirects me to task 3 as ive no longer completed that.