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PHP

Posted by koltton fox
koltton fox
2,576 Points

Create a New Float Variable named $float On with a value of 1.5. Without changing the value of $integer On or $float On,

Create a New Float Variable named $floatOne with a value of 1.5. Without changing the value of $integerOne or $floatOne, multiply $integerOne by $floatOne and display the results.

$results = $integerOne *$floatOne

echo $results

NOt working

Vijay Ramdass
Vijay Ramdass
13,275 Points
Vijay Ramdass
Vijay Ramdass
13,275 Points

Not sure if you are terminating your code or if it's in a php opening tag, but it should look something like this. 

<?php

$floatOne = 1.5;
$integerOne = 1; 

$results = $integerOne * $floatOne; 

echo $results; 

?>

2 Answers

Joel Benitez
Joel Benitez
749 Points
Joel Benitez
Joel Benitez
749 Points

Question:Create a New Float Variable named $floatOne with a value of 1.5. Without changing the value of $integerOne or $floatOne, multiply $integerOne by $floatOne and display the results.

Issue: I used the same php opening tag and it didn't work. why is it still asking "Are you sure you multiplied correctly?"

<?php

//Place your code below this comment $integerOne = 1; $integerTwo = 2; $floatOne = 1.5;

$integerOne = $integerOne + 5; var_dump($integerOne);

$integerTwo = $integerTwo - 1; var_dump($integerTwo);

$results = $integerOne * $floatOne;

echo($results); ?>

Vijay Ramdass
Vijay Ramdass
13,275 Points
Vijay Ramdass
Vijay Ramdass
13,275 Points

Hello,

Try removing the parenthesis around $results.

Joel Benitez
Joel Benitez
749 Points
Joel Benitez
Joel Benitez
749 Points

Vijay Ramdass

Thank you it worked!!