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Alphonse Cuccurullo
2,513 PointsDefining these two method's. Is confusing any assistants?
Define two methods in the editor:
A greeter method that takes a single string parameter, name, and returns a string greeting that person. (Make sure to use return and don't use print or puts.) A by_three? method that takes a single integer parameter, number, and returns true if that number is evenly divisible by three and false if not.
This is what i got so far. An it tells me " (ruby):6: warning: string literal in condition "
def greeter?(name) return name end
def by_three?(number) return true if number % 3 == 0 number !% 3 == 0 return false end
1 Answer
Arturo Alviar
15,739 PointsHi Alphonse,
Your are getting an error due to your second method. Your logic is correct but there are a few errors with your syntax. When doing an inline conditional, you can only have one condition statement. It is legal to say
return true if number % 3 === 0
But you cannot have another condition statement after that.
In this case, you can use an else statement so it would look something like this:
def by_three?(number)
if number % 3 == 0
return true
else
return false
end
A simple way to write this method is by returning a boolean with just one line like so:
def by_three?(number)
return number % 3 == 0
end
Hope this helps!