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Python Python Collections (2016, retired 2019) Lists Disemvowel

Disemvowel function seems to work but the test doesn't pass

Hello everybody. I tested this code and it seemed to work. However, the test doesn't pass. Have I done anything wrong here? Thanks!

disemvowel.py
def disemvowel(word):
    word = list(word)
    for letter in word:
        if letter.lower() in 'aeiou':
            word.remove(letter)
    return ''.join(word)

3 Answers

This works. I havent got it through first time i was on mobile device.

def disemvowel(word):
    my_list = list(word)
    for letter in word:
        if letter in "aeiouAEIOU":
            my_list.remove(letter)
    word = "".join(my_list)
    return word

Try this:

def disemvowel(word):
    vowels = ('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U')
    return ''.join([letter for letter in word if letter not in vowels])

If your not familiar with this syntax check out this course Python Comprehensions

You are very close. Almost done.

Instead of returning the joined word ''' return ''.join(word) ''' first seperate the list and the word

create new list out of the parameter word and use that to join with the word

def disemvowel(word):
    my_list = list(word)
    for letter in word:
        if letter.lower() in 'aeiou':
            my_list.remove(letter)
    word = ''.join(my_list)

i tried exactly what you out and it is still not passing....