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Barry May
3,963 PointsError cannot find symbol
When i try and run the below code the compiler doesn't seem to be able to evaluate the length of the args variable and I get the below error. Why is this? This code is exactly the same as in the video...
public class Hangman {
public static void main(String[] args) {
// Your amazing code goes here...
if (args.length() == 0) {
System.out.println("Please enter a word");
System.exit(0);
}
Game game = new Game(args[0]);
Prompter prompter = new Prompter(game);
prompter.play();
}
}
And the error is:
Hangman.java:5: error: cannot find symbol
if (args.length() == 0) {
^
symbol: method length()
location: variable args of type String[]
1 error
1 Answer
ISAIAH S
1,409 PointsYou don't need the "()" after length.
Barry May
3,963 PointsThanks Isaiah. Actually just figured it out myself!
ISAIAH S
1,409 Pointsyou are welcome and good job!
Steve Hunter
57,712 PointsSteve Hunter
57,712 PointsI see you're sorted, which is great.
Yes, the
lengthfor this exercise is a property not a method so the parentheses aren't needed. Be careful, though, as there are times when the length must be obtained with a method as there is no such property. Then, you'll need the brackets. Some arrays, for example, use a method to access their length.Steve.