Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript Basics (Retired) Making Decisions with Conditional Statements Improving the Random Number Guessing Game

Anthony Cruz
PLUS
Anthony Cruz
Courses Plus Student 2,035 Points

Even when I guess right I am wrong?

Followed the coding with the video and it seems I followed Dave pretty well, But when I test the program and guess correctly (example) it tells me sorry the number was 5. Even if i guessed 5. Can someone tell me what I am missing.

var correctGuess = false;
var randomNumber = Math.floor(Math.random() * 6 ) + 1;
var guess = prompt('I am thinking of a number between 1 and 6. What is it?');

if (parseInt(guess) === randomNumber ) {
  correctGuess = true;

} else if (parseInt(guess) > randomNumber) {
  var guessLess = prompt('Try Again. The number I am thinking of is less than '+ guess);
  if (parseInt(guessLess) === randomNumber){
  guessLess = true;
  }

} else if (parseInt(guess) < randomNumber) {
  var guessMore = prompt('Try Again. The number I am thinking of is More than ' + guess);
  if (parseInt(guessMore) === randomNumber) {
  guessMore = true;
  }
}

if ( correctGuess ) {
    document.write('<p>You guessed the number!</p>');
} else {
    document.write('<p>Sorry. The number was ' + randomNumber + '.</p>');
}
Kyle Knapp
Kyle Knapp
21,526 Points

Your final conditional if ( correctGuess ) { only checks whether correctGuess is true. It doesn't check guessLess or guessMore. So even if they are set to true, your final conditional isn't testing them, it's only testing correctGuess, which is set to false at the top of your program.

Since if ( correctGuess ) { is only testing correctGuess, it will always return false until correctGuess is re-set to true. So your sorry message will always print. (Unless you guess the number correct on your first try, which sets correctGuess here: if (parseInt(guess) === randomNumber ) { correctGuess = true; and will cause if ( correctGuess ) { to print your victory message.

So, you either need to test for guessMore and guessLess in your final conditional: if ( correctGuess || guessMore || guessLess) or you need to change both guessLess = true; and guessMore = true; to correctGuess = true.

In the first case, you are testing whether any of guessMore, guessLess or correctGuess is true, so if any one of them is true, even if the other two are false, the statement will evaluate to true and your victory message will print.

In the second case, you set correctGuess to true when either parseInt(guessMore) === randomNumber or parseInt(guessLess) === randomNumber). Since correctGuess is now set to true, your final conditional will pass and your victory message will print.

2 Answers

Steven Parker
Steven Parker
231,275 Points

It looks like you should get the correct result if you get it on the first guess. But on a second guess, the program sets either "guessLess" or "guessMore" instead of "correctGuess" so it will always be judged incorrect.

Fix the issue by changing each assignment to set "correctGuess".

In your else if() statements you have the boolean value being set to guessLess and guessMore. Try changing the variable correctGuess instead so it matches your ending if() statement.