Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Letter Game App Even or Odd Loop

Nico Pascher
Nico Pascher
5,857 Points
Posted by Nico Pascher
Nico Pascher
5,857 Points

even.py not working

Hey Guys,

any idea why this is not working?

Tanks a lot.

even.py 
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start > 0:
    num = random.randint(1, 99)
    if even_odd(num) == True:
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
        start = start - 1

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

You have an indentation error.

The last line is indented too far, so it is only done when the value is odd. The start counter should be decremented no matter which type of number was reported.

Also, while it is not an error, you never have to compare anything to True. Anything that could be compared to True can stand on it's own:

    if even_odd(num):
Nico Pascher
Nico Pascher
5,857 Points
Nico Pascher
Nico Pascher
5,857 Points

Thank you so much Steven!