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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Posted by vishruth Janagama
vishruth Janagama
1,498 Points

functions

Please fix this problem.

script.js 
function returnValue(name){
  var echo = name;
  return echo;
}
returnValue("anu");
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
James Moran
James Moran
7,271 Points

It is asking you to create a variable of echo outside of the function, and setting it to the value returned in the function.

If you make echo = name within the function, you can not use echo anywhere else. I'll give you a hint below. I hope that helps!

function returnValue(name){
  return name;
}

var echo = ?;

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

You're really close here! The echo variable is to be defined outside of the function and contain the result of calling the function. The only thing in the function should be the return statement which returns what you originally passed into it. Outside the function echo is declared and then we call/invoke/execute the function taking the string we pass to it. The function returns the string which then resides in our new echo variable. Take a look at your modified code to see what I mean:

function returnValue(name) {
  return name;
}

var echo = returnValue("Anu");