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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Review: Scope

Given the code below, what appears in the alert dialogue when this program runs?

var message = "Welcome!";
function setMessage() {
  message = "Go away!";
}
setMessage();
alert(message);

I can't understand why the alert message will be "Go away!" I guessed the alert message will be "Welcome!", because the var is out of the function.

I did the exact same thing, with the exact same reasoning!

4 Answers

Chris Shaw
Chris Shaw
26,676 Points

Hi grace Ji,

The reason why the message isn't "Welcome!" but instead "Go away!" is due to how variables work in the global scope versus the local scope. Anytime you omit the var keyword, JavaScript assumes the variable as been part of the global scope. In the case of this challenge, the value of the message variable is changed by the function call because we have omitted the var keyword.

If instead we change this so var is prefixed to the message variable in the setMessage function, it will become a local variable that is independent of the global variable.

Hope that helps.

Thank you Chris! :)

Robert Rydlewski
Robert Rydlewski
3,828 Points

Please help me understand this !!!

1st Quiz: Given the code below, what appears in the alert dialogue when this program runs?Ā ā€Ø

var message = "Welcome!"; function setMessage() { message = "Go away!"; } setMessage(); alert(message);

Answer ā€œGo away!ā€

Treehouse - "Ā Because theĀ varĀ keyword isn't used to declare aĀ messageĀ variable inside the function, the function overwrites the value in the global variableĀ message"

My understanding lol - "Ok..so the function overwrites the global variable message.. cool next question"

2nd quiz: Given the code below, what appears in the alert dialogue when this program runs?Ā 

var name = "Trish"; function setName() { var name = "Sarah"; } setName(); alert(name);

Answer: ā€œTrishā€ Ā  Treehouse - "TheĀ nameĀ variable outside the function is a global variable, so theĀ alert()Ā (which is also outside the function) accesses global variable."

my understanding " What the minute .. in the previous quiz you just told me the variable inside the function, the function overwrite value in global scope, but now it exactly opposite .. What I am missing ???? Please help!

Function is like a greedy girl.

Let's say ' function' is a little girl, and 'var' is a cookie.

1)f only the girl has a cookie; she doesn't share her cookie with other kids, and eat cookie by herself.

2)If another kid(= another function) has a cookie, and she doesn't have one; she takes the cookie from the kid and eat the cookie.

3)If another kid has a cookie, and she has one also; she takes the cookie from the kid, and save her cookie for later.

I still don't quite understand this, although the explanation where you use the girl and the cookie analogy is a great way to explain something, Grace =)

What I don't understand comes back to this: if I put the function (or any other code for that matter) inside curly braces { code } what would it matter to the code outside the curly braces if I write "var" or not?

Robert O'Toole
Robert O'Toole
6,366 Points

ill b honest the cookie thing helped me immensely... but this still stumps me. this is the first thing ive been really stumped on in Javascript now :(

Robert O'Toole
Robert O'Toole
6,366 Points

ok i think i finally get it! remember before in a previous lesson once you declare a variable you don't have to write var again? so lets say i make a var message=10..... later i only refer to it as message.

so since the var was not declared the message keyword acts like the gobal variable that was previously declared. IF we wrote var before message in the function, then the function would know to treat it like a separate variable within the function. hope this helps!