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Samandar Mirzayev
11,834 PointsGuys, I need your help I stuck in PHP. I coded but seems like an all correct but not working. I don't know why.
<?php include ("inc/data.php"); include ("inc/functions.php");
if(isset($_GET["id"])){ $id = $_GET["id"]; if(isset($catalog["id"])){ $item = $catalog["id"]; } }
if(!isset($item)){ header("location:catalog.php"); exit; }
$pageTitle = $item["title"]; $section = null;
include("inc/header.php"); ?>
<div class="section page"> <div class="wrapper"> <div class="media-picture"> <span> <img src="<?php echo $title['img'] ?>" alt="<?php echo $title['title'] ?>" /> </span> </div> </div> </div>
<?php include("inc/footer.php"); ?>
2 Answers
Matthew Bilz
15,829 PointsMy observation is that you never defined $title in your PHP block above the HTML. It first appears in the line that is causing the error, so before you use $title, you need to assign it a value. Either that or you meant something besides $title when referring to that variable on the line in question. I think that should help.
Samandar Mirzayev
11,834 Pointsbut for another page it is working anyway i will check again.
Samandar Mirzayev
11,834 Pointsyeah u right bro i have got it mine mistake thanks bro i really appriciated
Matthew Bilz
15,829 PointsAnother set of eyes always helps - I'm glad it worked!
Samandar Mirzayev
11,834 PointsSamandar Mirzayev
11,834 Pointsit is showing this line $pageTitle = $item["title"]; =>Notice: Undefined variable: item in /home/treehouse/workspace/details.php on line 17
and this line as well <img src="<?php echo $title['img'] ?>" alt="<?php echo $title['title'] ?>" /> => The requested URL /<br /><b>Notice</b>: Undefined variable: title in <b>/home/treehouse/workspace/details.php</b> on line <b>28</b><br /> was not found on this server. Why...???