Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

PHP Enhancing a Simple PHP Application Integrating Validation Errors Reviewing PHP Basics

Posted by Andrew McCombs
Andrew McCombs
4,309 Points

Help Challenge 3 of 3

You should have my favorite flavor of ice cream in a variable named $flavor, and now it's time to display it to the screen. Replace the underscores in the echo statement with the value from the flavor variable.

<?php include("flavor.php");

$flavor = get_flavor();

echo "Randy's favorite flavor of ice cream is " . echo $flavor . ".";

?>

I dont understand why this isnt working

3 Answers

Cole Wilkes
Cole Wilkes
4,556 Points
Cole Wilkes
Cole Wilkes
4,556 Points

Try removing the second "echo".

echo "Randy's favorite flavor of ice cream is " . $flavor . ".";

Brian van Vlymen
Brian van Vlymen
12,637 Points
Brian van Vlymen
Brian van Vlymen
12,637 Points

either way my code would works way. Which is not required to put the concentration and double quotes as long as its already inside the double quotes asking for variable.

<?php include("flavor.php");

$flavor = get_flavor();

echo "Randy's favorite flavor of ice cream is $flavor.";

?>

Andrew McCombs
Andrew McCombs
4,309 Points
Andrew McCombs
Andrew McCombs
4,309 Points

DUHHH!! I feel like an idiot!!