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Java Java Objects (Retired) Harnessing the Power of Objects Handling Exceptions

How can i catch the "drive" method being called?

I do not understand the question! The battery is empty but the code "kart.drive(2);" drives it two laps and I need to catch that, but how???

Main.java
public class Main {
    public static void main(String[] args) {
        GoKart kart = new GoKart("yellow");
        if (kart.isBatteryEmpty()) {
          System.out.println("The battery is empty");
        }
        kart.drive(2);
       throw new IllegalArgumentException("The battery is empty!);
    }
}

2 Answers

Hi Rubish,

At about 3:12 in the video Exceptions, Craig explains how to write a try / catch block.

Also, for this challenge, we don't want to throw an error, we just want to catch an error if one occurs.

If you're still stuck after watching that part of the video, please let me know.

Hope this helps,

Cheers

try {
        dispenser.load(400); 
      } catch (IllegalArgumentException iae) {
        System.out.println("Whoa there!");
        System.out.printf("The error was: %s%n", iae.getMessage());
      }

Above, is the code example to follow. Instead of dispenser.load, you are trying kart.drive