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iOS

How can I get rid of optional within the print statment

I am trying to print this statement: for dragonPlayer in dragons { print("Good Afternoon (dragonPlayer["guardianNames"])") } The output: Good Afternoon Optional("Jim and Jan Smith")

  • How can I remove optional?

3 Answers

You need to place a ! To remove the optional ?

Thank you Alex! Where should I place it?

dragons { print("Good Afternoon (dragonPlayer["guardianNames"]!)") }

If let dragonPlayers = dragonPlayer["guardianNames"] { print("Good Afternoon (dragonPlayers)") }

If think this is a best solution rather than force unwrap it.

Agreed