How is this equaling 6?

Question

Hello everyone,

In a test I came across a question that asks, "what does the following code output?"

<?php

$numbers = array (1 , 2 , 3 , 4 );

$total = count ( $numbers );

$sum = 0;

$output = "";

foreach( $numbers as $number ) {

$i = $i + 1;

if  ( $i < $total ) {

    $sum = $sum + $number;

}

}

$i = 0;

echo $sum;

?>

Could anyone explain to me how this is getting the equaling 6? Thanks so much in advance for any info. This has got me stumped.

Answer 1 · 2015-02-19T20:47:40Z

February 19, 2015 8:47pm

1 + 2 + 3 = 6

// move $i = $i + 1; to below your for loop 
//---or
// change if  ( $i < $total ) { to

if  ( $i <= $total ) {

Answer 2 · 2015-02-19T20:48:15Z

February 19, 2015 8:48pm

Hi Kenneth,

There are a few problems with your code.

First, you need to initialize $i before you start checking its value.

Second, the if statement is stopping before you go through it the 4th time, because $total is equal to 4. You could change your < to <=.

However, I would probably drop the $i and if statement altogether. A foreach loop will do this incrementing for you. Here's what I'd write:

<?php

$numbers = array (1 , 2 , 3 , 4 );

$sum = 0;

foreach( $numbers as $number ) {
   $sum = $sum + $number;
}

echo $sum;

?>

Hope this helps!

Greg

Answer 3 · 2015-02-19T21:05:14Z

February 19, 2015 9:05pm

Thanks Micah!

That makes sense now. I wasn't seeing how they were getting that number.

Greg,

It was a question straight from the "working with functions" test on here. I just wasn't how they were getting the outcome of 6.

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