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C# C# Basics (Retired) Perfect Variable Scope

Samuel Joseph
Samuel Joseph
5,406 Points
Posted by Samuel Joseph
Samuel Joseph
5,406 Points

I am stuck trying to figure out what they want for this section. My try/catch seems to be off and unsure how to fix it.

I am stuck trying to figure out what they want for this section. My try/catch seems to be off and unsure how to fix it.

Program.cs 
using System;

namespace Treehouse.CodeChallenges
{
    class Program
    {
        static void Main()
        {            
            input = Console.ReadLine();

            if (input == "quit")
            {
                string output = "Goodbye.";
            }
            else
            {
                try
                {

                string output = "You entered " + input + ".";
            }

            Console.WriteLine(output);
                }

            catch(FormatException)
            {
                Console.WriteLine("That is not a valid input");
                continue;
            }

        }
    }
}

1 Answer

Chris Jones
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Chris Jones
Java Web Development Techdegree Graduate 23,933 Points
Chris Jones
.a{fill-rule:evenodd;}techdegree seal-36
Chris Jones
Java Web Development Techdegree Graduate 23,933 Points

Hey Samuel!

There's no need for a try-catch block in this case. The code challenge is designed to test your understanding of variable scope.

There are two variables in the main method: input and output. You'll need to make a couple changes to pass the code challenge. Try this:

using System;

namespace Treehouse.CodeChallenges
{
    class Program
    {
        static void Main()
        {            
            string input = Console.ReadLine();
            string output;

            if (input == "quit")
            {
                output = "Goodbye.";
            }
            else
            {
                output = "You entered " + input + ".";
            }

            Console.WriteLine(output);
        }
    }
}

Notice how input is declared and initialized before the if-else statement. You need to at least declare a variable, which means to give it a type (int, string, boolean, etc).

You also need to declare the output variable, which is what I'm doing when I write string output;. However, we don't need to initialize the output variable yet, because that value we initialize it to depends on the logic in the if-else statement.

I hope that helps! Let me know if you have any more questions!