I cannot figure out what is the proper thing to put in the if statement inside the while loop!

Question

import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
num = random.randint(1, 99)
while start:
    if even_odd == 0:
        print ("{} is even".format(num))
    else:
        print ("{} is odd".format(num))
    start -=1
```even.py
import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
num = random.randint(1, 99)
while start:
    if even_odd == 0:
        print ("{} is even".format(num))
    else:
        print ("{} is odd".format(num))
    start -=1
```

Steven Parker · Answer

When calling "even_odd", you should pass it a number in parentheses as an argument.  And since it returns True or False directly, you don't need to compare it with anything.
Also, you'll need to pick the random numbers inside the loop otherwise all passes will test the same one.

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Courtney Erickson

Courtney Erickson

I cannot figure out what is the proper thing to put in the if statement inside the while loop!

1 Answer

Steven Parker

Steven Parker