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Java Java Basics Perfecting the Prototype Looping until the value passes

Posted by Charles Rotenberg
Charles Rotenberg
736 Points

I can't figure out an error I found in my syntax.

It says that the variable response is already described in a method I don't understand that is called run(). If someone could tell me where I went wrong that would be very helpful.

Example.java 
// I have initialized a java.io.Console for you. It is in a variable named console.

String response;
do{
String response = console.readLine("Do you understand do while loops? ");
}while (response.equalsIgnoreCase("no"));

2 Answers

Jacob Bergdahl
Jacob Bergdahl
29,118 Points
Jacob Bergdahl
Jacob Bergdahl
29,118 Points

You need to remove the "String" keyword from your loop. The reason why is because you've already declared the variable before the loop ("String response"), so every time you want to use "response" after that, you will simply call it without using "String".

Charles Rotenberg
Charles Rotenberg
736 Points

Thanks so much for the help!

Enrique Munguía
Enrique Munguía
14,311 Points
Enrique Munguía
Enrique Munguía
14,311 Points

You are declaring twice the variable response, within the do loop you can use it without typing the type String again

String response;
do{
    response = console.readLine("Do you understand do while loops? ");
}while (response.equalsIgnoreCase("no"));