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Python Python Basics (2015) Letter Game App Even or Odd Loop

Deniz Kahriman
Deniz Kahriman
8,538 Points

I can't figure out what I'm doing wrong with the last part of the challenge task :(

Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1.

import random start = 5 def even_odd(num): # If % 2 is 0, the number is even. # Since 0 is falsey, we have to invert it with not. return not num % 2 while start == True: num = random.randint(1, 99) if even_odd(num): print('{} is even'.format(num)) else: print('{} is odd'.format(num)) start -= 1

even.py
Make a while loop that runs until start is falsey.
Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99.
If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number.
Finally, decrement start by 1.

import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
while start == True:
    num = random.randint(1, 99)
    if even_odd(num):
        print('{} is even'.format(num))
    else:
        print('{} is odd'.format(num))
start -= 1

2 Answers

Steven Parker
Steven Parker
231,269 Points

To check for "truthy" just name the item.

The value of start is a number, so it will never equal True. But you can test it for "truthy" just by naming it:

while start:

This way, any number other than 0 will be considered "truthy", but when the value becomes 0 it will be "falsey".

Deniz Kahriman
Deniz Kahriman
8,538 Points

Thanks, Steven! Really appreciate it :)