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Java Java Basics Perfecting the Prototype Looping until the value passes

Posted by Sodiqin Zulfikri
Sodiqin Zulfikri
1,774 Points

I can't solve the challenge

Finally, using console.printf print out a formatted string that says "Because you said <response>, you passed the test!"

Example.java 
// I have initialized a java.io.Console for you. It is in a variable named console.
String response;
do {  
  response = console.readLine("Do you understand do while loops?  ");
if (response.equalsIgnoreCase("no")) {
  console.printf("Response. \n\n");
  console.printf("Because you said no, you passed the test!. \n\n");
        }
} while(response.equalsIgnoreCase("no"));

2 Answers

Simon Coates
Simon Coates
28,694 Points
Simon Coates
Simon Coates
28,694 Points

It looks like you got confused about what they were asking. It wants you to print the message when the response breaks out of the do while block. that is - when the response is not equal to "No". This also requires that the output string use the response variable. As such, the answer is probably:

String response;
do {
  response = console.readLine("Do you understand do while loops?  ");
} while (response.equals("No"));
 console.printf("Because you said %s, you passed the test!", response);
vikas soni
vikas soni
50 Points
vikas soni
vikas soni
50 Points

String response; do {
response = console.readLine("Do you understand do while loops? "); console.printf("%s Because you said "+response+", you passed the test!"); } } while(response.equals("No"));