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Python Python Collections (2016, retired 2019) Sets Set Math

Posted by Hussein Amr
Hussein Amr
2,461 Points

I don't get the question

any ideas

sets.py 
COURSES = {
    "Python Basics": {"Python", "functions", "variables",
                      "booleans", "integers", "floats",
                      "arrays", "strings", "exceptions",
                      "conditions", "input", "loops"},
    "Java Basics": {"Java", "strings", "variables",
                    "input", "exceptions", "integers",
                    "booleans", "loops"},
    "PHP Basics": {"PHP", "variables", "conditions",
                   "integers", "floats", "strings",
                   "booleans", "HTML"},
    "Ruby Basics": {"Ruby", "strings", "floats",
                    "integers", "conditions",
                    "functions", "input"}
}
def covers(topics):
    inters = []
    for k,v in COURSES:
        if k & v:
            inters.append(k)
    return inters
Hussein Amr
Hussein Amr
2,461 Points

Victor Santiago it didn't work bruh

1 Answer

Ismail KOÇ
Ismail KOÇ
1,748 Points
Ismail KOÇ
Ismail KOÇ
1,748 Points 
if k & v:

this statement intersection compares keys and values, this challenge wants intersection your argument (topics) and values of COURSES for write course name (COURSES[key]) and return intersection.

if input_arg & COURSES[key]:

check this and write what do you need.

Michael Hulet
Michael Hulet
47,913 Points

Hi Ismail! For future reference, it's frowned upon around here to write a copy/paste answer with no explanation at all. If you'd like, feel free to re-post your code, but be sure to thoroughly explain why it's correct. Also, in Python, the & does a bitwise AND operation, not a logical and, which is probably what you want. A logical and in Python is just the word and. Happy coding, and thanks for helping out around the Community!

Ismail KOÇ
Ismail KOÇ
1,748 Points

i will pay attention this for next time

Hussein Amr
Hussein Amr
2,461 Points

Ismail KOÇ did that but didn't work

def covers(topics):
    for v in COURSES:
        if topics & (COURSES[v]):
            return topics.intersection(COURSES[v])
Ismail KOÇ
Ismail KOÇ
1,748 Points 
def covers(topics):                                  # ------>    No space
    for v in COURSES:                                # ------>    4 spaces 
        if topics & (COURSES[v]):                    # ------>    8 spaces
            return topics.intersection(COURSES[v])   # ------>    12 spaces

python has space sensitive for ex:

for i in range(1,5)           # loop 1  -----> No space 
    for j in [6,7,8]          # loop 2  -----> 4 space
        for k in (9,0)        # loop 3  -----> 8 space

in this program :

  • loop 3 in loop 2
  • loop 2 in loop 1

look your code again:

def covers(topics):                                  # ------>    No space
    for v in COURSES:                                # ------>    4 spaces 
        if topics & (COURSES[v]):                    # ------>    8 spaces
            return topics.intersection(COURSES[v])   # ------>    12 spaces
  • for loop in (covers) function
  • if condution in for loop
  • return in if condution
  • so you need to move return 8 space backward (delete 8 spaces) because return needs to independent of for loop.