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Declan Nolan
1,069 PointsI don't know what to do.
I don't know how to do the second task of the Counting Scrabble Tiles assignment can someone please help.
public class ScrabblePlayer {
// A String representing all of the tiles that this player has
private String tiles;
private char letter;
public ScrabblePlayer() {
tiles = "";
}
public String getTiles() {
return tiles;
}
public void addTile(char tile) {
tiles += tile;
}
public boolean hasTile(char tile) {
return tiles.indexOf(tile) != -1;
}
public int getCountOfLetter(char letter) {
return 0;
}
}
// This code is here for example purposes only
public class Example {
public static void main(String[] args) {
ScrabblePlayer player1 = new ScrabblePlayer();
player1.addTile('d');
player1.addTile('d');
player1.addTile('p');
player1.addTile('e');
player1.addTile('l');
player1.addTile('u');
ScrabblePlayer player2 = new ScrabblePlayer();
player2.addTile('z');
player2.addTile('z');
player2.addTile('y');
player2.addTile('f');
player2.addTile('u');
player2.addTile('z');
int count = 0;
// This would set count to 1 because player1 has 1 'p' tile in her collection of tiles
count = player1.getCountOfLetter('p');
// This would set count to 2 because player1 has 2 'd'' tiles in her collection of tiles
count = player1.getCountOfLetter('d');
// This would set 0, because there isn't an 'a' tile in player1's tiles
count = player1.getCountOfLetter('a');
// This will return 3 because player2 has 3 'z' tiles in his collection of tiles
count = player2.getCountOfLetter('z');
// This will return 1 because player2 has 1 'f' tiles in his collection of tiles
count = player2.getCountOfLetter('f');
}
}
1 Answer
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Travis Alstrand
Treehouse Project ReviewerIt's wanting us to establish a variable to use as a counter, so an int
makes sense here.
Then we need to loop over tiles
and for every "tile" in that string, we want to see if it's the same as the letter
passed in as an argument. If it is, we increment our counter. Finally, we return the counter.
I used a for loop here but there are other loops you can use for this of course.
public int getCountOfLetter(char letter) {
int counter = 0;
for (char tile : tiles.toCharArray()) {
if (tile == letter) {
counter++;
}
}
return counter;
}