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PHP

jason chan
jason chan
31,009 Points

I don't understand the if statement in mike4shirts

<?php
function get_product_single($sku) {

    require(ROOT_PATH . "inc/database.php");

    try {
        $results = $db->prepare("SELECT name, price, img, sku, paypal FROM products WHERE sku = ?");
        $results->bindParam(1,$sku);
        $results->execute();
    } catch (Exception $e) {
        echo "Data could not be retrieved from the database.";
        exit;
    }

    $product = $results->fetch(PDO::FETCH_ASSOC);

    if ($product === false) return $product;

    $product["sizes"] = array();

    try { 
        $results = $db->prepare("SELECT product_sku, size_id, size FROM `products_sizes` INNER JOIN sizes ON products_sizes.size_id = sizes.id WHERE product_sku = ? order by `order`");
        $results->bindParam(1,$sku);
        $results->execute();
    } catch (Exception $e) {
        echo "data could not be retrieved";
        exit;
    }

    while( $row = $results->fetch(PDO::FETCH_ASSOC)) {

        $product["sizes"][] = $row["size"];

    }

    return $product;
}

I don't understand the if product === false why does the product run?

Edited to format code by adding <?php in the code block.

1 Answer

If the fetch fails, then it returns false. So on failure, the method returns $product, which is false. That goes to shirt.php, which has the following code:

<?php
if (empty($product)) {
    header("Location: " . BASE_URL . "shirts/");
    exit();
}

I am guessing that false is also empty, so the site is redirected back to shirts instead of the individual page.