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Python Python Basics (2015) Python Data Types String concatenation

Nova Anderson
Nova Anderson
176 Points
Posted by Nova Anderson
Nova Anderson
176 Points

I don't understand why I'm receiving an undefined error when I'm giving the undefined concept a value by setting Name=

SOS

strings.py 
Name = Grace

2 Answers

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

You're defining Name, but where was Grace defined?

Perhaps you meant to assign name with the literal string "Grace" — but you just forgot to put the quotes around it.

Gosh I forgot to check the challenge itself, but as Alexander pointed out, you have to be careful about case. So you don't want to define Name here anyway. Define name according to the challenge instructions.

Alexander Davison
Alexander Davison
65,469 Points
Alexander Davison
Alexander Davison
65,469 Points

To add to Steven Parker's post, the variable name Name and the variable name name are different. At first glance, they look the same, but since Python is case-sensitive, meaning that uppercase and lowercase letters are different, they are different. The challenge wanted you to call it name, not Name!

-–—–-–—–-

The value of the variable doesn't matter to the challenge, as long as the value is a string. It's only the name of the variable is important to the challenge.