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Java Java Basics Perfecting the Prototype Looping until the value passes

Farouk Charkas
Farouk Charkas
1,957 Points

I have a method run() error!

I have written the following code below, but I have this error "JavaTester.java:123: error: variable response is already defined in method run()", anybody know how I can fix this? Thanks in advance!

Example.java
// I have initialized a java.io.Console for you. It is in a variable named console.

String response;

do {
  String response = console.readLine("Do you understand do while loops?");
  if (response.equalsIgnoreCase("no")) {
  }
} while (response.equalsIgnoreCase("no"));

6 Answers

Jon Kussmann
PLUS
Jon Kussmann
Courses Plus Student 7,254 Points
String response;

do {
  response = console.readLine("Do you understand do while loops?");
  if (response.equalsIgnoreCase("no")) {
  }
} while (response.equalsIgnoreCase("no"));

You don't put "String" in front of the second "response" because is declaring a new variable called "response" which you already have, which is why you got the original error.

Jon Kussmann
PLUS
Jon Kussmann
Courses Plus Student 7,254 Points

Hi Farouk,

Try deleting

String response;

In your very first line. Hope that helps. If not please let me know.

Farouk Charkas
Farouk Charkas
1,957 Points

That helped, but then I got those Bummer! thing from Treehouse, with the same code, but i get the error "Did you create a new String called response",