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Full Stack JavaScript Techdegree Student 1,016 PointsI was trying to use While Loop but encountered a problem which I dont know how to name it
What I want to do is:
- print "Goodbye!" if 0 is entered.
- print "Thanks for your order!" if 1 is entered.
- If any number besides 0 or 1 is input, you will be asked to enter again. For 3 times in a While loop.
But what really happened is that I could not get to the "else" block. Even if I got the number right, it just didn't print out the messages. Can anyone please point out what is wrong with my code?
So here's a part of my code:
confirm_purchase = int(input("Enter 0 to cancel, 1 to procede with your order: "))
attempt = 2
while confirm_purchase != 0 or 1:
if attempt <= 0:
print("Too many attempts. Come back later!")
break
confirm_purchase = input("{} attempt(s) left. Try again: ".format(attempt))
attempt -= 1
else:
if confirm_purchase == 0:
print("Goodbye!")
if confirm_purchase == 1:
print("Thanks for your order!")
1 Answer
Chris Freeman
Treehouse Moderator 68,441 PointsThe issue is with the or
. You have:
while confirm_purchase != 0 or 1:
which is True if while confirm_purchase != 0
or 1
. The latter, 1
, is synonymous with True
so this expression will always be true.
You need to be explicit:
while confirm_purchase != 0 or confirm_purchase != 1:
# or maybe
while confirm_purchase not in (0, 1):
Post back if you need more help. Good luck!!
sv vs
Full Stack JavaScript Techdegree Student 925 Pointssv vs
Full Stack JavaScript Techdegree Student 925 PointsHello, after I fix the code, when I try to run it I still cannot get the messages from my 2nd attempt.
If I get the value correct (0 or 1) at the first attempt, the message is printed. No problem and totally nice! But from the second attempt forward it keeps telling me to retry even if I input the correct value. Help please!
Chris Freeman
Treehouse Moderator 68,441 PointsChris Freeman
Treehouse Moderator 68,441 PointsIt wasn’t obvious, but the first setting of
confirm_purchase
is typecast to anint
. Inside thewhile
loop it remains a string. So, add anint()
wrapper or add”0”, “1”
to the while condition choices.