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PHP

Posted by Ray LeDuc
Ray LeDuc
1,525 Points

If statement always evaluates to false.

I have "hand to eye" evaluated both $stringOne and the statement in the comparison and they both seem to me to be exactly the same. I must just be over looking something I am just not sure what it is. code as follows

<?php

$name = "Ray";
$stringOne = 'Learning to display ';
$stringOne .= '"Hello ';
$stringOne .= $name;
$stringOne .= '!" to the screen.';
$stringOne = $stringOne."\n";

echo $stringOne;

$isReady = true;
//var_dump($isReady);
$isReady = false;
//var_dump($isReady);

//var_dump(1 + "2)");

$a = 10;
$b = "10";

//var_dump($a == $b);
//var_dump($a === $b);

//var_dump($stringOne == 'Learning to display "Hello Ray!" to the screen.');

if($stringOne == 'Learning to display "Hello Ray!" to the screen.'){
  echo 'The values match';
} else {
  echo 'The values DO NOT match';
} 


?>

2 Answers

andren
andren
28,558 Points
andren
andren
28,558 Points

You add a line break to the $stringOne variable:

$stringOne = $stringOne."\n";

Which you do not do with the string you are comparing it to, that is what makes them different. If you remove the line where you add the line break or change your if statement's condition to this:

$stringOne == 'Learning to display "Hello Ray!" to the screen.'."\n"

Then you will find that the two strings match.

Ray LeDuc
Ray LeDuc
1,525 Points
Ray LeDuc
Ray LeDuc
1,525 Points

@andren Thanks for the help/explanation.