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Alex Young
4,265 Pointsif statement query?
Hi,
I'm trying to put everything i've learnt plus a little research but it's working with rolling the dice i get numbers from 0-6 fine but my if statement is not working
<?php $numbers = array('1','2','3','4','5','6'); ?>
<form action="index.php" class="dice" name="dice"> <input type="submit" value="Roll">
<?php echo(array_rand($numbers,1)); ?>
</form>
<?php
if ($numbers > 3) { echo "You Rolled a high number"; } else { echo "Not Today"; }
?>
Alex Young
4,265 PointsNope was just random idea to practice if statement, array really and just building it up more i learn
Konrad Pilch
2,435 Pointsaa okay . I think you might try swich too , if php has it, but it should xd im new to this too but how im learning is that im doing things i want , so i went throw the treehouse tutroaials, some of them and then i went off doing registration form and so on . But i like the small ideas like making the dice :) teach small things that will be for sure cool but what more improve on the skill .
Happy Coding! :) :D
2 Answers
Brad Van Skyhawk
28,489 PointsHi,
You need a assign you random number to a variable and then test it. You are using the array in your if statement.
For example:
<?php $num = array_rand($numbers,1); if ($num > 3) { echo "You Rolled a high number"; } else { echo "Not Today"; }
Alex Young
4,265 PointsThank you :)
Konrad Pilch
2,435 PointsKonrad Pilch
2,435 PointsHI, a bit off the topic but could i ask you what game are you doing? are you just making a rolling dice that displays a number or you make the computer guess and you roll the cide and it tells you your if statement ?