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BACAR D JAURA
536 Pointsif/else if/else Print the message from the table when a user enters a number in the corresponding range.
"""C# string input = Console.ReadLine();
int temperature = int.Parse(input);
if(temperature < 21)
{
System.Console.WriteLine("Too cold!")
}
else if (temperature >= 21 && temperature <= 22)
{
System.Console.WriteLine("Just Right.");
}
else
{
System.Console.WriteLine("Too hot!");
}
"""
string input = Console.ReadLine();
int temperature = int.Parse(input);
if(temperature < 21)
{
Console.WriteLine("Too cold!")
}
else if(temperature >= 21 && temperature <= 22)
{
Console.WriteLine("Just Right.");
}
else
{
Console.WriteLine("Too hot!");
}
2 Answers
Jason Anders
Treehouse Moderator 145,860 PointsHi Bacar,
You're code is correct except for one small syntax error. If you click preview in the challenge, it gives you the clue to where the error is:
StudentsCode.cs(13,1): error CS1002: ; expected
Compilation failed: 1 error(s), 0 warnings
As the "; expected" states, you are missing a semicolon for the code block inside the if clause. Once that's put in, your code passes.
Other than that... Nice Job!! :)
BACAR D JAURA
536 PointsHi Jason,
Thank you legend, I didn't realise that. Thank you so much for your advise.
Take Care :)