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Sarah Shealy
5,950 PointsI'm confused about why this isn't passing.
I have no idea why this isn't passing. I'm pretty sure it's something simple but I'm missing it. These are the instructions:
"Next, let’s move the flavors array into that function. This task has two steps. (1) Move the code that creates the flavors array from index.php into the get_all_flavors() function in flavors.php. (2) Add code at the end of the function so that it returns the array of flavors back to whatever code calls it."
<?php
// MODEL FILE function get_all_flavors() { $flavors = array( "Jalapeno So Spicy", "Avocado Chocolate", "Peppermint", "Vanilla", "Cake Batter", "Cookie Dough" );
return = $flavors; } ?>
3 Answers
adamdonatello
27,485 PointsHi Sarah!
The only thing I can see is that on your return statement you have included a "=" sign which I don't think is required. I Hope this helps :)
<?php
function get_all_flavors() {
$flavors = array( "Jalapeno So Spicy", "Avocado Chocolate", "Peppermint", "Vanilla", "Cake Batter", "Cookie Dough" );
return $flavors;
}
?>
Sarah Shealy
5,950 PointsI knew it would be something simple! I always miss the "=".
Thanks!
Stephen Van Delinder
21,457 Pointsreturn = $flavors; } ?>
= assigns a variable in php. You just want to return $flavors.