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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Roscoe Coney
Roscoe Coney
13,124 Points
Posted by Roscoe Coney
Roscoe Coney
13,124 Points

Im DROWNING in this question!! plz help

QUESTION:

Now that you've created the returnValue function, call it, by passing it a literal string value -- a series of characters in quote marks like this: 'My argument'. Store the results of the function in a variable named echo.

I have below:

function returnValue (car) {

  var echo = "My argument"

return (car)

}
Shilpa K
Shilpa K
12,722 Points
Shilpa K
Shilpa K
12,722 Points

If you can correct your markup for it to be easier to read, that would be helpful. But already I can see that you need to put an " = " to assign your variable var echo, not " - "

2 Answers

Matthew Ong
Matthew Ong
6,041 Points
Matthew Ong
Matthew Ong
6,041 Points

You need to return the argument passed into the function, not a defined string. You are also missing a few semicolons. This should work:

function returnValue (car) {

 return (car);

 }
var echo = returnValue('hello');
Roscoe Coney
Roscoe Coney
13,124 Points
Roscoe Coney
Roscoe Coney
13,124 Points

I tried that and I received the following error message

Bummer! To call a function type its name and a pair of parentheses like these returnValue('hello').

Matthew Ong
Matthew Ong
6,041 Points
Matthew Ong
Matthew Ong
6,041 Points

Oh it wants you to actually call the function. I've updated my answer, try it now.

Roscoe Coney
Roscoe Coney
13,124 Points
Roscoe Coney
Roscoe Coney
13,124 Points

Perfect!! Thanks, I see what I did wrong!

Richard Duncan
Richard Duncan
5,568 Points
Richard Duncan
Richard Duncan
5,568 Points

Roscoe Coney Hi! If you're satisfied with the answer it's good practice to mark it as 'best answer' to encourage help in the future and also should any student struggle with this themselves they will have a reference to it :)

MUZ140875 Joseph Chivasa
MUZ140875 Joseph Chivasa
7,758 Points
MUZ140875 Joseph Chivasa
MUZ140875 Joseph Chivasa
7,758 Points

function returnValue(a){ return a;} var echo = "returnValue("a")";

i keep getting it wrong

zabe sangary
zabe sangary
2,657 Points

You doing it wrong totally. Advise you to watch the video over and over.

function returnValue(a){ return (a); }

var echo = returnValue("Much to learn still have.");