Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialAli Siddiqi
4,413 PointsIn python, my task one, sundaes = available.split(", ") does not pass anymore for some reason what is the problem?
My task is to:
Alright, let's finish making our menu. Combine the sundaes list into a new variable named display_menu, where each item in the list is rejoined together by a comma and a space (", "). Then reassign the menu variable to use the existing variable and .format() to replace the placeholder with the new string in display_menu. If you're really brave, you can even accomplish this all on the same line where menu is currently being set.
available = "banana split;hot fudge;cherry;malted;black and white"
sundaes = available.split(", ")
menu = "Our available flavors are: {}.".format(", ".join(display_menu))
display_menu = sundaes.join(", ")
2 Answers
Steven Parker
231,269 PointsYou get that message whenever you have a syntax error. In this case, it's because you reference "display_menu" before it is created, and on the last line you have applied "join" to a list and given it a string argument. But "join" is a string method that takes a list argument.
You don't actually need that last line at all, since you do everything on the line before it. But you will need to put your "split" argument back the way it was when you passed task 1, and join using "sundaes" instead of "display_menu".
Ali Siddiqi
4,413 PointsThank you