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![Steve Mbouadeu](https://secure.gravatar.com/avatar/b5de172c6f813e6a4f7c578d635bdb7d?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Steve Mbouadeu
Courses Plus Student 119 PointsIt says create a new variable name, I am amusing its a string so what is wrong?
Its not compiling :(
// I've imported java.io.Console for you. It is stored in a variable called console for you.
String name = console.readLine();
3 Answers
![Jason Anders](https://uploads.teamtreehouse.com/production/profile-photos/3512822/micro_Jason_s-Pic.jpg)
Jason Anders
Treehouse Moderator 145,859 PointsHey Steve,
You're on the right track, but the readLine
method is expecting an argument (eg. "What is your name?"). Just add that to your code and you're good to go. :)
Keep Coding!
![Sameera Sy](https://secure.gravatar.com/avatar/e700c41ad3c22e17311b9aca69152e2b?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Sameera Sy
2,349 PointsHi Steve!
According to the docs the readLine()
method takes an argument! But you aren't passing anything. Just pass an empty string instead!
String name = console.readLine("");
![Steve Mbouadeu](https://secure.gravatar.com/avatar/b5de172c6f813e6a4f7c578d635bdb7d?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Steve Mbouadeu
Courses Plus Student 119 PointsThank You very much!