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1,319 PointsJSON Exception caught
hi,
I try to run the following code and get a JSON exception: No value for America/Los_Angeles (I am currently not in Los Angeles).
private CurrentWeather getCurrentDetails(String jsonData) throws JSONException {
JSONObject forecast = new JSONObject(jsonData);
String timeZone =forecast.getString("timezone");
Log.i(TAG,"From JSON: " + timeZone);
JSONObject currently = forecast.getJSONObject("currently");
CurrentWeather currentWeather = new CurrentWeather();
currentWeather.setHumidity(currently.getDouble("humidity"));
currentWeather.setTime(currently.getLong("time"));
currentWeather.setIcon(currently.getString("icon"));
currentWeather.setPrecipitation(currently.getDouble("precipProbability"));
currentWeather.setSummary(currently.getString("summary"));
currentWeather.setTemperature(currently.getDouble("temperature"));
currentWeather.setTtimeZone(currently.getString(timeZone));
Log.d(TAG, currentWeather.getFormattedTime());
return new CurrentWeather();
}
the exception is thrown from the line: "currentWeather.setTtimeZone(currently.getString(timeZone));".
Does anyone have a solution for this problem?
Thanks
1 Answer
Steve Hunter
57,712 PointsHi there,
I assume your method in CurrentWeather
is setTtimeZone
? That would throw a different error; suggest correcting the typo as that may cause confusion.
You can either use the timezone variable you have already created:
String timeZone =forecast.getString("timezone");
in the currentWeather
line:
currentWeather.setTtimeZone(currently.getString(timeZone)); // change this
currentWeather.setTtimeZone(timeZone); // to this
Or you can make sure you're pulling the time zone from currently
with this:
currentWeather.setTtimeZone(currently.getString("timezone"));
I can't answer your LA question; that depends on the lat/long you sent the API.
I hope that helps.
Steve.