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Python Introducing Lists Build an Application Multidimensional Musical Groups

ARUN DAMODARAN
ARUN DAMODARAN
733 Points
Posted by ARUN DAMODARAN
ARUN DAMODARAN
733 Points

List Challenge Question

Hello All,

Below is the code that I had written to solve this LIST Challenge question and I got the results as well.

just though to check if the below said code is correct.

Appreciate your responses.

groups.py 
musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
]
group_counter = 1
for group in musical_groups:
    print("{}".format(", ".join(group)))
    group_counter += 1

2 Answers

Vikas Choudhary
PLUS
Vikas Choudhary
Courses Plus Student 9,836 Points
Vikas Choudhary
Vikas Choudhary
Courses Plus Student 9,836 Points

Your answer is correct but why you have variable 'group_counter'? It is not required here

ARUN DAMODARAN
ARUN DAMODARAN
733 Points
ARUN DAMODARAN
ARUN DAMODARAN
733 Points

Yes Vishal, there is no need for group_counter variable and it was declared for someother purpose.