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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Pedro Meio-Dia
Pedro Meio-Dia
3,896 Points

Make a while loop that runs until start is falsey.

What do I wrong, please?

even.py 
import random

def even_odd(num):
    start = 5
    return not num % 2
    while start <=5:
        num = random.randint(1,99)
    if num % 2 = 0:
        print('{} is even'.format(num))
        start -= 1
    else:
        print('{} is odd'.format(num))
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

It looks like you added code to the even_odd function.

Your code should go after the function, so the first line of the new code won't be indented. Skipping a blank line after the function wouldn't hurt, either.

Also, when you test that something is not "falsey", you just name it. You don't need any comparison expression.