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CSS

my :checked + class wont work

I wont to make a hamburger menu bet the :checked selector wont work. It works wen i do

.toggle:checked {
  display: block;

bet not with de + .menu what did I do wrong?

 <nav>
        <div class="nav">
          <label class="hamburger__menu" for="toggle">&#9776</label>
          <input class="toggle" type="checkbox" id="toggle">
        </div>

        <div class="menu-box">
          <ul class="menu">
            <li class="menu__item"><a class="item__link" href="#">home</a></li>
            <li class="menu__item menu__item--yellow"><a class="item__link" href="#">humo@festivals</a></li>
            <li class="menu__item"><a class="item__link" href="#">humor</a></li>
            <li class="menu__item menu__item--red"><a class="item__link" href="#">video</a></li>
            <li class="menu__item"><a class="item__link" href="#">fotospecials</a></li>
            <li class="menu__item"><a class="item__link" href="#">nu in humo</a></li>
            <li class="menu__item"><a class="item__link" href="#">tv/film</a></li>
            <li class="menu__item"><a class="item__link" href="#">actua</a></li>
            <li class="menu__item"><a class="item__link" href="#">muziek</a></li>
            <li class="menu__item"><a class="item__link" href="#">boeken</a></li>
            <li class="menu__item"><a class="item__link" href="#">humo sapiens</a></li>
          </ul>
        </div>
      </nav>
.menu {
  padding: 0 2rem 0 1rem;
  display: none;
}

.toggle {
  display: none;

  &:checked + .menu {
    display: block;
  }
}

En when you do .menu:checked?

zimri lejien It is not working bet thx for commenting :)

1 Answer

Steven Parker
Steven Parker
231,248 Points

This isn't CSS code (the syntax coloring gives you a clue). Did you mean to compile it (or use SCSS syntax)?

But even with that fixed, the "toggle" input and the "menu" list are not siblings (nor are they adjacent), since they are each contained in different div's. So the sibling selector doesn't select the menu.

sorry indeed this is scss it will be converted to css in the end. but because they are not siblings it cannot work?

Steven Parker
Steven Parker
231,248 Points

It can't work with the current HTML structure and a CSS sibling selector. But it's reasonably easy to do in JavaScript.