Need help in PHP Switch Statement?

Question

While I am doing coding in Java, we can use two output to give actual number in switch like:

In Java:

case 3: case 4: case 5: echo "They all are same"; echo "But this is the actual value is " + x; break; // Output - But the actual value is 3

In PHP:

case 3:case 4:case 5: echo "They all are same"; echo "But the actual value " + $x; break; // Output - "3"

In php, it is showing me "They all are same 3" Why it is not showing the second echo output like "But the actual value is 3"

Full Code

<?php

$x = 3;

switch ($x){ case 1: echo "This is 1"; break;

case 2:
    echo "This is 2";
    break;

case 3:case 4:case 5:
    echo "They all are same ";
    echo "But this is the actual value is " + $x;
    break;

default:
    echo "None of the value is correct";
    break;

}

Answer 1 · 2016-12-26T05:59:09Z

December 26, 2016 5:59am

In Java you concatenate with a " + ", in PHP you use a dot " . ".

<?php
  $x = 3;
  switch ($x){ 

    case 1: 
      echo "This is 1"; 
      break;

    case 2:
      echo "This is 2";
      break;

    case 3:
    case 4:
    case 5:
      echo "They all are same ";
      echo "But this is the actual value is " . $x;
      break;

    default:
      echo "None of the value is correct";
      break;
  }
?>

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Vijesh Arora

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Need help in PHP Switch Statement?

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Philip Gales

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