Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript Introducing the Practice

Piotr Manczak
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Piotr Manczak
Front End Web Development Techdegree Graduate 29,363 Points
Posted by Piotr Manczak
.a{fill-rule:evenodd;}techdegree seal-36
Piotr Manczak
Front End Web Development Techdegree Graduate 29,363 Points

One solution

Good afternoon My solution is a bit different. What do you think about it?

const selectAnimal = document.getElementById("animals");
const selectBreed = document.getElementById("breeds");
const options = document.querySelectorAll("[data-breed]");
selectAnimal.addEventListener("change", () => {
    options.forEach(option => option.hidden = option.dataset.breed != selectAnimal.value);
    if(selectBreed != ""){
        selectBreed.value = "";
    }
});

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Apparently, you realized that if an item is hidden, it cannot be selected and therefore does not also need to be disabled.

The fact that you're thinking of effective alternative strategies is evidence of your learning progress and grasp of the material. Good job!   :+1: