Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Shopping List App Break

Posted by Brianna Washington
Brianna Washington
576 Points

Oops, I forgot that I need to break out of the loop when the current item is the string "STOP". Help me add that code!

I think this is a syntax issue but can't seem to find it?

breaks.py 
def loopy(items):

     for item in items:

        if item == 'STOP':
            break
        else:
            print(item)

    # Code goes here

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

It looks OK to me, so I pasted it in and it passes task 2 of the challenge.

It won't pass task 1, but the objective for that one is different (and simpler).